7[4-(3x-8)]=42x+140

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Solution for 7[4-(3x-8)]=42x+140 equation:


Simplifying
7[4 + -1(3x + -8)] = 42x + 140

Reorder the terms:
7[4 + -1(-8 + 3x)] = 42x + 140
7[4 + (-8 * -1 + 3x * -1)] = 42x + 140
7[4 + (8 + -3x)] = 42x + 140

Combine like terms: 4 + 8 = 12
7[12 + -3x] = 42x + 140
[12 * 7 + -3x * 7] = 42x + 140
[84 + -21x] = 42x + 140

Reorder the terms:
84 + -21x = 140 + 42x

Solving
84 + -21x = 140 + 42x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-42x' to each side of the equation.
84 + -21x + -42x = 140 + 42x + -42x

Combine like terms: -21x + -42x = -63x
84 + -63x = 140 + 42x + -42x

Combine like terms: 42x + -42x = 0
84 + -63x = 140 + 0
84 + -63x = 140

Add '-84' to each side of the equation.
84 + -84 + -63x = 140 + -84

Combine like terms: 84 + -84 = 0
0 + -63x = 140 + -84
-63x = 140 + -84

Combine like terms: 140 + -84 = 56
-63x = 56

Divide each side by '-63'.
x = -0.8888888889

Simplifying
x = -0.8888888889

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